How accurate is this JEE Main rank predictor?

This predictor uses the official NTA formula and the latest candidate data. Actual ranks may vary slightly due to normalization, tie-breaking, and final candidate count.

What is the formula for JEE Main rank calculation?

Expected Rank = (100 - Percentile) × Total Candidates ÷ 100. For JEE Main 2026, approximately 15.38 lakh unique candidates appeared.

What percentile is required to qualify for JEE Advanced?

For General category, approximately 93-95 percentile is needed. OBC-NCL requires around 79-82 percentile. SC/ST cutoffs are lower.

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JEE Main 2026 Rank Predictor

Enter your percentile or expected marks to instantly calculate your All India Rank (AIR) and category rank.

Predict Your Rank

Fill in your details below to get an instant estimate.

Calculate Using *

Category *

Your Percentile * Enter your NTA percentile score

Your Estimated

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All India Rank (CRL)

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College Prospects

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Important

This is an estimate based on the official NTA formula and previous year trends. Actual rank may vary due to normalization, tie-breaking, and final candidate count.

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How This Predictor Works

Based on the official NTA percentile formula and 2026 candidate data.

NTA Percentile Formula

Rank = (100 − Percentile) × Total Candidates ÷ 100. For 2026, approximately 15.38 lakh unique candidates appeared.

Category-Wise Calculation

CRL rank is calculated directly. OBC/SC/ST/EWS ranks are estimated based on historical reservation ratios.

Marks vs Percentile

If you enter marks, we estimate your percentile using historical marks-vs-percentile trends for JEE Main.

Frequently Asked Questions

How accurate is this rank predictor?

It uses the official NTA formula and the latest candidate count. Actual ranks may vary slightly due to normalization, tie-breaking, and final candidate numbers.

For General category, approximately 93–95 percentile. OBC-NCL around 79–82 percentile. SC/ST cutoffs are lower.

No. This predicts JEE Main rank only. JEE Advanced has a different ranking system based on aggregate marks across Paper 1 and Paper 2.

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